The expression 3 [ sin ^4 { 3pi2 - alpha } + sin ^4 (3pi + alpha ) ] - 2 [ sin ^6 ( pi2 + alpha ) . + sin ^6 (5pi - alpha )] is equal to :
![Let f : (0, pi)→ R be a twice differentiable function such that limit t→x f(x)sint - f(t)sinxt - x = sin^2x for all xepsilon (0, pi) .If f (pi6) = - Let f : (0, pi)→ R be a twice differentiable function such that limit t→x f(x)sint - f(t)sinxt - x = sin^2x for all xepsilon (0, pi) .If f (pi6) = -](https://dwes9vv9u0550.cloudfront.net/images/1106744/a5c369a6-9df2-476b-92fe-d0c82c9b64c0.jpg)
Let f : (0, pi)→ R be a twice differentiable function such that limit t→x f(x)sint - f(t)sinxt - x = sin^2x for all xepsilon (0, pi) .If f (pi6) = -
![If sin A = 4/5,pi/2<A<pi and cos B = 5/13,3pi/2<B<2pi , find (i) sin (A + B) , (ii) cos (A - B) , (iii) tan (A - B) If sin A = 4/5,pi/2<A<pi and cos B = 5/13,3pi/2<B<2pi , find (i) sin (A + B) , (ii) cos (A - B) , (iii) tan (A - B)](https://dwes9vv9u0550.cloudfront.net/images/4437113/361c8f4e-203a-4149-942d-29d5ac362c6c.jpg)
If sin A = 4/5,pi/2<A<pi and cos B = 5/13,3pi/2<B<2pi , find (i) sin (A + B) , (ii) cos (A - B) , (iii) tan (A - B)
![Let f:R -> ( 0,(2pi)/2] defined as f(x) = cot^-1 (x^2-4x + alpha) Then the smallest integral value of alpha such that, f(x) is into function is Let f:R -> ( 0,(2pi)/2] defined as f(x) = cot^-1 (x^2-4x + alpha) Then the smallest integral value of alpha such that, f(x) is into function is](https://d10lpgp6xz60nq.cloudfront.net/ss/web/1668560.jpg)
Let f:R -> ( 0,(2pi)/2] defined as f(x) = cot^-1 (x^2-4x + alpha) Then the smallest integral value of alpha such that, f(x) is into function is
![Unitary transformation for Poincaré beams on different parts of Poincaré sphere | Scientific Reports Unitary transformation for Poincaré beams on different parts of Poincaré sphere | Scientific Reports](https://media.springernature.com/lw685/springer-static/image/art%3A10.1038%2Fs41598-020-71189-2/MediaObjects/41598_2020_71189_Fig5_HTML.png)